It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 491 502 is not a prime number.
For example, 491 502 can be divided by 2: 491 502 / 2 = 245 751.
For 491 502 to be a prime number, it would have been required that 491 502 has only two divisors, i.e., itself and 1.
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491 502 is an even number, because it is evenly divisible by 2: 491 502 / 2 = 245 751.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 491 502 is about 701.072.
Thus, the square root of 491 502 is not an integer, and therefore 491 502 is not a square number.
The square of a number (here 491 502) is the result of the product of this number (491 502) by itself (i.e., 491 502 × 491 502); the square of 491 502 is sometimes called "raising 491 502 to the power 2", or "491 502 squared".
The square of 491 502 is 241 574 216 004 because 491 502 × 491 502 = 491 5022 = 241 574 216 004.
As a consequence, 491 502 is the square root of 241 574 216 004.
The multiples of 491 502 are all integers evenly divisible by 491 502, that is all numbers such that the remainder of the division by 491 502 is zero. There are infinitely many multiples of 491 502. The smallest multiples of 491 502 are: