It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 496 498 is not a prime number.
For example, 496 498 can be divided by 2: 496 498 / 2 = 248 249.
For 496 498 to be a prime number, it would have been required that 496 498 has only two divisors, i.e., itself and 1.
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496 498 is an even number, because it is evenly divisible by 2: 496 498 / 2 = 248 249.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 496 498 is about 704.626.
Thus, the square root of 496 498 is not an integer, and therefore 496 498 is not a square number.
The square of a number (here 496 498) is the result of the product of this number (496 498) by itself (i.e., 496 498 × 496 498); the square of 496 498 is sometimes called "raising 496 498 to the power 2", or "496 498 squared".
The square of 496 498 is 246 510 264 004 because 496 498 × 496 498 = 496 4982 = 246 510 264 004.
As a consequence, 496 498 is the square root of 246 510 264 004.
The multiples of 496 498 are all integers evenly divisible by 496 498, that is all numbers such that the remainder of the division by 496 498 is zero. There are infinitely many multiples of 496 498. The smallest multiples of 496 498 are: