Is 1012500 a prime number?

1 012 500 is an even number, because it is evenly divisible by 2: 1 012 500 / 2 = 506 250.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1 012 500 is about 1 006.231.

Thus, the square root of 1 012 500 is not an integer, and therefore 1 012 500 is not a square number.

The square of a number (here 1 012 500) is the result of the product of this number (1 012 500) by itself (i.e., 1 012 500 × 1 012 500); the square of 1 012 500 is sometimes called "raising 1 012 500 to the power 2", or "1 012 500 squared".

The square of 1 012 500 is 1 025 156 250 000 because 1 012 500 × 1 012 500 = 1 012 500² = 1 025 156 250 000.

As a consequence, 1 012 500 is the square root of 1 025 156 250 000.

1 012 500 is a number with 7 digits.

The multiples of 1 012 500 are all integers evenly divisible by 1 012 500, that is all numbers such that the remainder of the division by 1 012 500 is zero. There are infinitely many multiples of 1 012 500. The smallest multiples of 1 012 500 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 1 012 500 too, since 0 × 1 012 500 = 0
• 1 012 500: indeed, 1 012 500 is a multiple of itself, since 1 012 500 is evenly divisible by 1 012 500 (we have 1 012 500 / 1 012 500 = 1, so the remainder of this division is indeed zero)
• 2 025 000: indeed, 2 025 000 = 1 012 500 × 2
• 3 037 500: indeed, 3 037 500 = 1 012 500 × 3
• 4 050 000: indeed, 4 050 000 = 1 012 500 × 4
• 5 062 500: indeed, 5 062 500 = 1 012 500 × 5
• etc.

• Preceding numbers: …1 012 498, 1 012 499
• Following numbers: 1 012 501, 1 012 502…

Nearest numbers from 1 012 500

• Preceding prime number: 1 012 489
• Following prime number: 1 012 507

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• 1 012 500 est-il un nombre premier ?