Is 113002001 a prime number?

113 002 001 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 113 002 001 is about 10 630.240.

Thus, the square root of 113 002 001 is not an integer, and therefore 113 002 001 is not a square number.

The square of a number (here 113 002 001) is the result of the product of this number (113 002 001) by itself (i.e., 113 002 001 × 113 002 001); the square of 113 002 001 is sometimes called "raising 113 002 001 to the power 2", or "113 002 001 squared".

The square of 113 002 001 is 12 769 452 230 004 000 because 113 002 001 × 113 002 001 = 113 002 001² = 12 769 452 230 004 000.

As a consequence, 113 002 001 is the square root of 12 769 452 230 004 000.

113 002 001 is a number with 9 digits.

The multiples of 113 002 001 are all integers evenly divisible by 113 002 001, that is all numbers such that the remainder of the division by 113 002 001 is zero. There are infinitely many multiples of 113 002 001. The smallest multiples of 113 002 001 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 113 002 001 too, since 0 × 113 002 001 = 0
• 113 002 001: indeed, 113 002 001 is a multiple of itself, since 113 002 001 is evenly divisible by 113 002 001 (we have 113 002 001 / 113 002 001 = 1, so the remainder of this division is indeed zero)
• 226 004 002: indeed, 226 004 002 = 113 002 001 × 2
• 339 006 003: indeed, 339 006 003 = 113 002 001 × 3
• 452 008 004: indeed, 452 008 004 = 113 002 001 × 4
• 565 010 005: indeed, 565 010 005 = 113 002 001 × 5
• etc.

• Preceding numbers: …113 001 999, 113 002 000
• Following numbers: 113 002 002, 113 002 003…

Nearest numbers from 113 002 001

• Preceding prime number: 113 001 961
• Following prime number: 113 002 039

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