It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 113 013 513 is not a prime number.
For example, 113 013 513 can be divided by 3: 113 013 513 / 3 = 37 671 171.
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For 113 013 513 to be a prime number, it would have been required that 113 013 513 has only two divisors, i.e., itself and 1.
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113 013 513 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 113 013 513 is about 10 630.781.
Thus, the square root of 113 013 513 is not an integer, and therefore 113 013 513 is not a square number.
The square of a number (here 113 013 513) is the result of the product of this number (113 013 513) by itself (i.e., 113 013 513 × 113 013 513); the square of 113 013 513 is sometimes called "raising 113 013 513 to the power 2", or "113 013 513 squared".
The square of 113 013 513 is 12 772 054 120 601 168 because 113 013 513 × 113 013 513 = 113 013 5132 = 12 772 054 120 601 168.
As a consequence, 113 013 513 is the square root of 12 772 054 120 601 168.
113 013 513 is a number with 9 digits.
The multiples of 113 013 513 are all integers evenly divisible by 113 013 513, that is all numbers such that the remainder of the division by 113 013 513 is zero. There are infinitely many multiples of 113 013 513. The smallest multiples of 113 013 513 are: