It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 113 529 023 is not a prime number.
For example, 113 529 023 can be divided by 89: 113 529 023 / 89 = 1 275 607.
For 113 529 023 to be a prime number, it would have been required that 113 529 023 has only two divisors, i.e., itself and 1.
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113 529 023 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 113 529 023 is about 10 655.000.
Thus, the square root of 113 529 023 is not an integer, and therefore 113 529 023 is not a square number.
The square of a number (here 113 529 023) is the result of the product of this number (113 529 023) by itself (i.e., 113 529 023 × 113 529 023); the square of 113 529 023 is sometimes called "raising 113 529 023 to the power 2", or "113 529 023 squared".
The square of 113 529 023 is 12 888 839 063 334 528 because 113 529 023 × 113 529 023 = 113 529 0232 = 12 888 839 063 334 528.
As a consequence, 113 529 023 is the square root of 12 888 839 063 334 528.
113 529 023 is a number with 9 digits.
The multiples of 113 529 023 are all integers evenly divisible by 113 529 023, that is all numbers such that the remainder of the division by 113 529 023 is zero. There are infinitely many multiples of 113 529 023. The smallest multiples of 113 529 023 are: