It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 113 938 is not a prime number.
For example, 113 938 can be divided by 2: 113 938 / 2 = 56 969.
For 113 938 to be a prime number, it would have been required that 113 938 has only two divisors, i.e., itself and 1.
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113 938 is an even number, because it is evenly divisible by 2: 113 938 / 2 = 56 969.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 113 938 is about 337.547.
Thus, the square root of 113 938 is not an integer, and therefore 113 938 is not a square number.
The square of a number (here 113 938) is the result of the product of this number (113 938) by itself (i.e., 113 938 × 113 938); the square of 113 938 is sometimes called "raising 113 938 to the power 2", or "113 938 squared".
The square of 113 938 is 12 981 867 844 because 113 938 × 113 938 = 113 9382 = 12 981 867 844.
As a consequence, 113 938 is the square root of 12 981 867 844.
The multiples of 113 938 are all integers evenly divisible by 113 938, that is all numbers such that the remainder of the division by 113 938 is zero. There are infinitely many multiples of 113 938. The smallest multiples of 113 938 are: