It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 116 642 113 is not a prime number.
For example, 116 642 113 can be divided by 7: 116 642 113 / 7 = 16 663 159.
For 116 642 113 to be a prime number, it would have been required that 116 642 113 has only two divisors, i.e., itself and 1.
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116 642 113 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 116 642 113 is about 10 800.098.
Thus, the square root of 116 642 113 is not an integer, and therefore 116 642 113 is not a square number.
The square of a number (here 116 642 113) is the result of the product of this number (116 642 113) by itself (i.e., 116 642 113 × 116 642 113); the square of 116 642 113 is sometimes called "raising 116 642 113 to the power 2", or "116 642 113 squared".
The square of 116 642 113 is 13 605 382 525 104 768 because 116 642 113 × 116 642 113 = 116 642 1132 = 13 605 382 525 104 768.
As a consequence, 116 642 113 is the square root of 13 605 382 525 104 768.
116 642 113 is a number with 9 digits.
The multiples of 116 642 113 are all integers evenly divisible by 116 642 113, that is all numbers such that the remainder of the division by 116 642 113 is zero. There are infinitely many multiples of 116 642 113. The smallest multiples of 116 642 113 are: