It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 117 109 023 is not a prime number.
For example, 117 109 023 can be divided by 3: 117 109 023 / 3 = 39 036 341.
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For 117 109 023 to be a prime number, it would have been required that 117 109 023 has only two divisors, i.e., itself and 1.
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117 109 023 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 117 109 023 is about 10 821.692.
Thus, the square root of 117 109 023 is not an integer, and therefore 117 109 023 is not a square number.
The square of a number (here 117 109 023) is the result of the product of this number (117 109 023) by itself (i.e., 117 109 023 × 117 109 023); the square of 117 109 023 is sometimes called "raising 117 109 023 to the power 2", or "117 109 023 squared".
The square of 117 109 023 is 13 714 523 268 014 528 because 117 109 023 × 117 109 023 = 117 109 0232 = 13 714 523 268 014 528.
As a consequence, 117 109 023 is the square root of 13 714 523 268 014 528.
117 109 023 is a number with 9 digits.
The multiples of 117 109 023 are all integers evenly divisible by 117 109 023, that is all numbers such that the remainder of the division by 117 109 023 is zero. There are infinitely many multiples of 117 109 023. The smallest multiples of 117 109 023 are: