Is 117324413 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
Yes, 117 324 413 is a prime number.
Indeed, the definition of a prime numbers is to have exactly two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 117 324 413, the only two divisors are 1 and 117 324 413. Therefore 117 324 413 is a prime number.
As a consequence, 117 324 413 is only a multiple of 1 and 117 324 413.
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Since 117324413 is a prime number, 117324413 is also a deficient number, that is to say 117324413 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 117324413 without 117324413 itself (that is 1, by definition!).