It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 118 373 018 is not a prime number.
For example, 118 373 018 can be divided by 2: 118 373 018 / 2 = 59 186 509.
For 118 373 018 to be a prime number, it would have been required that 118 373 018 has only two divisors, i.e., itself and 1.
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118 373 018 is an even number, because it is evenly divisible by 2: 118 373 018 / 2 = 59 186 509.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 118 373 018 is about 10 879.936.
Thus, the square root of 118 373 018 is not an integer, and therefore 118 373 018 is not a square number.
The square of a number (here 118 373 018) is the result of the product of this number (118 373 018) by itself (i.e., 118 373 018 × 118 373 018); the square of 118 373 018 is sometimes called "raising 118 373 018 to the power 2", or "118 373 018 squared".
The square of 118 373 018 is 14 012 171 390 428 324 because 118 373 018 × 118 373 018 = 118 373 0182 = 14 012 171 390 428 324.
As a consequence, 118 373 018 is the square root of 14 012 171 390 428 324.
118 373 018 is a number with 9 digits.
The multiples of 118 373 018 are all integers evenly divisible by 118 373 018, that is all numbers such that the remainder of the division by 118 373 018 is zero. There are infinitely many multiples of 118 373 018. The smallest multiples of 118 373 018 are: