It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 118 413 402 is not a prime number.
For example, 118 413 402 can be divided by 2: 118 413 402 / 2 = 59 206 701.
For 118 413 402 to be a prime number, it would have been required that 118 413 402 has only two divisors, i.e., itself and 1.
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118 413 402 is an even number, because it is evenly divisible by 2: 118 413 402 / 2 = 59 206 701.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 118 413 402 is about 10 881.792.
Thus, the square root of 118 413 402 is not an integer, and therefore 118 413 402 is not a square number.
The square of a number (here 118 413 402) is the result of the product of this number (118 413 402) by itself (i.e., 118 413 402 × 118 413 402); the square of 118 413 402 is sometimes called "raising 118 413 402 to the power 2", or "118 413 402 squared".
The square of 118 413 402 is 14 021 733 773 213 604 because 118 413 402 × 118 413 402 = 118 413 4022 = 14 021 733 773 213 604.
As a consequence, 118 413 402 is the square root of 14 021 733 773 213 604.
118 413 402 is a number with 9 digits.
The multiples of 118 413 402 are all integers evenly divisible by 118 413 402, that is all numbers such that the remainder of the division by 118 413 402 is zero. There are infinitely many multiples of 118 413 402. The smallest multiples of 118 413 402 are: