It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 118 642 012 is not a prime number.
For example, 118 642 012 can be divided by 2: 118 642 012 / 2 = 59 321 006.
For 118 642 012 to be a prime number, it would have been required that 118 642 012 has only two divisors, i.e., itself and 1.
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118 642 012 is an even number, because it is evenly divisible by 2: 118 642 012 / 2 = 59 321 006.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 118 642 012 is about 10 892.291.
Thus, the square root of 118 642 012 is not an integer, and therefore 118 642 012 is not a square number.
The square of a number (here 118 642 012) is the result of the product of this number (118 642 012) by itself (i.e., 118 642 012 × 118 642 012); the square of 118 642 012 is sometimes called "raising 118 642 012 to the power 2", or "118 642 012 squared".
The square of 118 642 012 is 14 075 927 011 408 144 because 118 642 012 × 118 642 012 = 118 642 0122 = 14 075 927 011 408 144.
As a consequence, 118 642 012 is the square root of 14 075 927 011 408 144.
118 642 012 is a number with 9 digits.
The multiples of 118 642 012 are all integers evenly divisible by 118 642 012, that is all numbers such that the remainder of the division by 118 642 012 is zero. There are infinitely many multiples of 118 642 012. The smallest multiples of 118 642 012 are: