It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 118 812 138 is not a prime number.
For example, 118 812 138 can be divided by 2: 118 812 138 / 2 = 59 406 069.
For 118 812 138 to be a prime number, it would have been required that 118 812 138 has only two divisors, i.e., itself and 1.
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118 812 138 is an even number, because it is evenly divisible by 2: 118 812 138 / 2 = 59 406 069.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 118 812 138 is about 10 900.098.
Thus, the square root of 118 812 138 is not an integer, and therefore 118 812 138 is not a square number.
The square of a number (here 118 812 138) is the result of the product of this number (118 812 138) by itself (i.e., 118 812 138 × 118 812 138); the square of 118 812 138 is sometimes called "raising 118 812 138 to the power 2", or "118 812 138 squared".
The square of 118 812 138 is 14 116 324 136 131 044 because 118 812 138 × 118 812 138 = 118 812 1382 = 14 116 324 136 131 044.
As a consequence, 118 812 138 is the square root of 14 116 324 136 131 044.
118 812 138 is a number with 9 digits.
The multiples of 118 812 138 are all integers evenly divisible by 118 812 138, that is all numbers such that the remainder of the division by 118 812 138 is zero. There are infinitely many multiples of 118 812 138. The smallest multiples of 118 812 138 are: