It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 121 012 016 is not a prime number.
For example, 121 012 016 can be divided by 2: 121 012 016 / 2 = 60 506 008.
For 121 012 016 to be a prime number, it would have been required that 121 012 016 has only two divisors, i.e., itself and 1.
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121 012 016 is an even number, because it is evenly divisible by 2: 121 012 016 / 2 = 60 506 008.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 121 012 016 is about 11 000.546.
Thus, the square root of 121 012 016 is not an integer, and therefore 121 012 016 is not a square number.
The square of a number (here 121 012 016) is the result of the product of this number (121 012 016) by itself (i.e., 121 012 016 × 121 012 016); the square of 121 012 016 is sometimes called "raising 121 012 016 to the power 2", or "121 012 016 squared".
The square of 121 012 016 is 14 643 908 016 384 256 because 121 012 016 × 121 012 016 = 121 012 0162 = 14 643 908 016 384 256.
As a consequence, 121 012 016 is the square root of 14 643 908 016 384 256.
121 012 016 is a number with 9 digits.
The multiples of 121 012 016 are all integers evenly divisible by 121 012 016, that is all numbers such that the remainder of the division by 121 012 016 is zero. There are infinitely many multiples of 121 012 016. The smallest multiples of 121 012 016 are: