It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 121 013 042 is not a prime number.
For example, 121 013 042 can be divided by 2: 121 013 042 / 2 = 60 506 521.
For 121 013 042 to be a prime number, it would have been required that 121 013 042 has only two divisors, i.e., itself and 1.
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121 013 042 is an even number, because it is evenly divisible by 2: 121 013 042 / 2 = 60 506 521.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 121 013 042 is about 11 000.593.
Thus, the square root of 121 013 042 is not an integer, and therefore 121 013 042 is not a square number.
The square of a number (here 121 013 042) is the result of the product of this number (121 013 042) by itself (i.e., 121 013 042 × 121 013 042); the square of 121 013 042 is sometimes called "raising 121 013 042 to the power 2", or "121 013 042 squared".
The square of 121 013 042 is 14 644 156 334 093 764 because 121 013 042 × 121 013 042 = 121 013 0422 = 14 644 156 334 093 764.
As a consequence, 121 013 042 is the square root of 14 644 156 334 093 764.
121 013 042 is a number with 9 digits.
The multiples of 121 013 042 are all integers evenly divisible by 121 013 042, that is all numbers such that the remainder of the division by 121 013 042 is zero. There are infinitely many multiples of 121 013 042. The smallest multiples of 121 013 042 are: