Is 121022015 a prime number?

121 022 015 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 121 022 015 is about 11 001.001.

Thus, the square root of 121 022 015 is not an integer, and therefore 121 022 015 is not a square number.

The square of a number (here 121 022 015) is the result of the product of this number (121 022 015) by itself (i.e., 121 022 015 × 121 022 015); the square of 121 022 015 is sometimes called "raising 121 022 015 to the power 2", or "121 022 015 squared".

The square of 121 022 015 is 14 646 328 114 660 224 because 121 022 015 × 121 022 015 = 121 022 015² = 14 646 328 114 660 224.

As a consequence, 121 022 015 is the square root of 14 646 328 114 660 224.

121 022 015 is a number with 9 digits.

The multiples of 121 022 015 are all integers evenly divisible by 121 022 015, that is all numbers such that the remainder of the division by 121 022 015 is zero. There are infinitely many multiples of 121 022 015. The smallest multiples of 121 022 015 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 121 022 015 too, since 0 × 121 022 015 = 0
• 121 022 015: indeed, 121 022 015 is a multiple of itself, since 121 022 015 is evenly divisible by 121 022 015 (we have 121 022 015 / 121 022 015 = 1, so the remainder of this division is indeed zero)
• 242 044 030: indeed, 242 044 030 = 121 022 015 × 2
• 363 066 045: indeed, 363 066 045 = 121 022 015 × 3
• 484 088 060: indeed, 484 088 060 = 121 022 015 × 4
• 605 110 075: indeed, 605 110 075 = 121 022 015 × 5
• etc.

• Preceding numbers: …121 022 013, 121 022 014
• Following numbers: 121 022 016, 121 022 017…

Nearest numbers from 121 022 015

• Preceding prime number: 121 022 009
• Following prime number: 121 022 023

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• 121 022 015 est-il un nombre premier ?