It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 130 508 012 is not a prime number.
For example, 130 508 012 can be divided by 2: 130 508 012 / 2 = 65 254 006.
For 130 508 012 to be a prime number, it would have been required that 130 508 012 has only two divisors, i.e., itself and 1.
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130 508 012 is an even number, because it is evenly divisible by 2: 130 508 012 / 2 = 65 254 006.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 130 508 012 is about 11 424.010.
Thus, the square root of 130 508 012 is not an integer, and therefore 130 508 012 is not a square number.
The square of a number (here 130 508 012) is the result of the product of this number (130 508 012) by itself (i.e., 130 508 012 × 130 508 012); the square of 130 508 012 is sometimes called "raising 130 508 012 to the power 2", or "130 508 012 squared".
The square of 130 508 012 is 17 032 341 196 192 144 because 130 508 012 × 130 508 012 = 130 508 0122 = 17 032 341 196 192 144.
As a consequence, 130 508 012 is the square root of 17 032 341 196 192 144.
130 508 012 is a number with 9 digits.
The multiples of 130 508 012 are all integers evenly divisible by 130 508 012, that is all numbers such that the remainder of the division by 130 508 012 is zero. There are infinitely many multiples of 130 508 012. The smallest multiples of 130 508 012 are: