Is 141012013 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
Yes, 141 012 013 is a prime number.
Indeed, the definition of a prime numbers is to have exactly two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 141 012 013, the only two divisors are 1 and 141 012 013. Therefore 141 012 013 is a prime number.
As a consequence, 141 012 013 is only a multiple of 1 and 141 012 013.
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Since 141012013 is a prime number, 141012013 is also a deficient number, that is to say 141012013 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 141012013 without 141012013 itself (that is 1, by definition!).