Is 1423 a prime number? What are the divisors of 1423?

## Is 1423 a prime number?

Yes, 1423 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 1423, the only two divisors are 1 and 1423. Therefore 1423 is a prime number.

As a consequence, 1423 is only a multiple of 1 and 1423.

Since 1423 is a prime number, 1423 is also a deficient number, that is to say 1423 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 1423 without 1423 itself (that is 1, by definition!).

## Parity of 1423

1423 is an odd number, because it is not evenly divisible by 2.

## Is 1423 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1423 is about 37.723.

Thus, the square root of 1423 is not an integer, and therefore 1423 is not a square number.

Anyway, 1423 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 1423?

The square of a number (here 1423) is the result of the product of this number (1423) by itself (i.e., 1423 × 1423); the square of 1423 is sometimes called "raising 1423 to the power 2", or "1423 squared".

The square of 1423 is 2 024 929 because 1423 × 1423 = 14232 = 2 024 929.

As a consequence, 1423 is the square root of 2 024 929.

## Number of digits of 1423

1423 is a number with 4 digits.

## What are the multiples of 1423?

The multiples of 1423 are all integers evenly divisible by 1423, that is all numbers such that the remainder of the division by 1423 is zero. There are infinitely many multiples of 1423. The smallest multiples of 1423 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 1423 too, since 0 × 1423 = 0
• 1423: indeed, 1423 is a multiple of itself, since 1423 is evenly divisible by 1423 (we have 1423 / 1423 = 1, so the remainder of this division is indeed zero)
• 2 846: indeed, 2 846 = 1423 × 2
• 4 269: indeed, 4 269 = 1423 × 3
• 5 692: indeed, 5 692 = 1423 × 4
• 7 115: indeed, 7 115 = 1423 × 5
• etc.

## Nearest numbers from 1423

Find out whether some integer is a prime number