It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 142 523 016 is not a prime number.
For example, 142 523 016 can be divided by 2: 142 523 016 / 2 = 71 261 508.
For 142 523 016 to be a prime number, it would have been required that 142 523 016 has only two divisors, i.e., itself and 1.
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142 523 016 is an even number, because it is evenly divisible by 2: 142 523 016 / 2 = 71 261 508.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 142 523 016 is about 11 938.300.
Thus, the square root of 142 523 016 is not an integer, and therefore 142 523 016 is not a square number.
The square of a number (here 142 523 016) is the result of the product of this number (142 523 016) by itself (i.e., 142 523 016 × 142 523 016); the square of 142 523 016 is sometimes called "raising 142 523 016 to the power 2", or "142 523 016 squared".
The square of 142 523 016 is 20 312 810 089 736 256 because 142 523 016 × 142 523 016 = 142 523 0162 = 20 312 810 089 736 256.
As a consequence, 142 523 016 is the square root of 20 312 810 089 736 256.
142 523 016 is a number with 9 digits.
The multiples of 142 523 016 are all integers evenly divisible by 142 523 016, that is all numbers such that the remainder of the division by 142 523 016 is zero. There are infinitely many multiples of 142 523 016. The smallest multiples of 142 523 016 are: