It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 1 624 388 is not a prime number.
For example, 1 624 388 can be divided by 2: 1 624 388 / 2 = 812 194.
For 1 624 388 to be a prime number, it would have been required that 1 624 388 has only two divisors, i.e., itself and 1.
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1 624 388 is an even number, because it is evenly divisible by 2: 1 624 388 / 2 = 812 194.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1 624 388 is about 1 274.515.
Thus, the square root of 1 624 388 is not an integer, and therefore 1 624 388 is not a square number.
The square of a number (here 1 624 388) is the result of the product of this number (1 624 388) by itself (i.e., 1 624 388 × 1 624 388); the square of 1 624 388 is sometimes called "raising 1 624 388 to the power 2", or "1 624 388 squared".
The square of 1 624 388 is 2 638 636 374 544 because 1 624 388 × 1 624 388 = 1 624 3882 = 2 638 636 374 544.
As a consequence, 1 624 388 is the square root of 2 638 636 374 544.
The multiples of 1 624 388 are all integers evenly divisible by 1 624 388, that is all numbers such that the remainder of the division by 1 624 388 is zero. There are infinitely many multiples of 1 624 388. The smallest multiples of 1 624 388 are: