Is 1823 a prime number? What are the divisors of 1823?

## Is 1823 a prime number?

Yes, 1823 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 1823, the only two divisors are 1 and 1823. Therefore 1823 is a prime number.

As a consequence, 1823 is only a multiple of 1 and 1823.

Therefore year 1823 was a prime year.

Since 1823 is a prime number, 1823 is also a deficient number, that is to say 1823 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 1823 without 1823 itself (that is 1, by definition!).

## Parity of 1823

1823 is an odd number, because it is not evenly divisible by 2.

## Is 1823 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1823 is about 42.697.

Thus, the square root of 1823 is not an integer, and therefore 1823 is not a square number.

Anyway, 1823 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 1823?

The square of a number (here 1823) is the result of the product of this number (1823) by itself (i.e., 1823 × 1823); the square of 1823 is sometimes called "raising 1823 to the power 2", or "1823 squared".

The square of 1823 is 3 323 329 because 1823 × 1823 = 18232 = 3 323 329.

As a consequence, 1823 is the square root of 3 323 329.

## Number of digits of 1823

1823 is a number with 4 digits.

## What are the multiples of 1823?

The multiples of 1823 are all integers evenly divisible by 1823, that is all numbers such that the remainder of the division by 1823 is zero. There are infinitely many multiples of 1823. The smallest multiples of 1823 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 1823 too, since 0 × 1823 = 0
• 1823: indeed, 1823 is a multiple of itself, since 1823 is evenly divisible by 1823 (we have 1823 / 1823 = 1, so the remainder of this division is indeed zero)
• 3 646: indeed, 3 646 = 1823 × 2
• 5 469: indeed, 5 469 = 1823 × 3
• 7 292: indeed, 7 292 = 1823 × 4
• 9 115: indeed, 9 115 = 1823 × 5
• etc.

## Nearest numbers from 1823

Find out whether some integer is a prime number