Is 1973 a prime number? What are the divisors of 1973?

## Is 1973 a prime number?

Yes, 1973 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 1973, the only two divisors are 1 and 1973. Therefore 1973 is a prime number.

As a consequence, 1973 is only a multiple of 1 and 1973.

Therefore year 1973 was a prime year.

Since 1973 is a prime number, 1973 is also a deficient number, that is to say 1973 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 1973 without 1973 itself (that is 1, by definition!).

## Parity of 1973

1973 is an odd number, because it is not evenly divisible by 2.

## Is 1973 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 1973 is about 44.418.

Thus, the square root of 1973 is not an integer, and therefore 1973 is not a square number.

Anyway, 1973 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 1973?

The square of a number (here 1973) is the result of the product of this number (1973) by itself (i.e., 1973 × 1973); the square of 1973 is sometimes called "raising 1973 to the power 2", or "1973 squared".

The square of 1973 is 3 892 729 because 1973 × 1973 = 19732 = 3 892 729.

As a consequence, 1973 is the square root of 3 892 729.

## Number of digits of 1973

1973 is a number with 4 digits.

## What are the multiples of 1973?

The multiples of 1973 are all integers evenly divisible by 1973, that is all numbers such that the remainder of the division by 1973 is zero. There are infinitely many multiples of 1973. The smallest multiples of 1973 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 1973 too, since 0 × 1973 = 0
• 1973: indeed, 1973 is a multiple of itself, since 1973 is evenly divisible by 1973 (we have 1973 / 1973 = 1, so the remainder of this division is indeed zero)
• 3 946: indeed, 3 946 = 1973 × 2
• 5 919: indeed, 5 919 = 1973 × 3
• 7 892: indeed, 7 892 = 1973 × 4
• 9 865: indeed, 9 865 = 1973 × 5
• etc.

## Nearest numbers from 1973

Find out whether some integer is a prime number