It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 2 013 678 is not a prime number.
For example, 2 013 678 can be divided by 2: 2 013 678 / 2 = 1 006 839.
For 2 013 678 to be a prime number, it would have been required that 2 013 678 has only two divisors, i.e., itself and 1.
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2 013 678 is an even number, because it is evenly divisible by 2: 2 013 678 / 2 = 1 006 839.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 2 013 678 is about 1 419.041.
Thus, the square root of 2 013 678 is not an integer, and therefore 2 013 678 is not a square number.
The square of a number (here 2 013 678) is the result of the product of this number (2 013 678) by itself (i.e., 2 013 678 × 2 013 678); the square of 2 013 678 is sometimes called "raising 2 013 678 to the power 2", or "2 013 678 squared".
The square of 2 013 678 is 4 054 899 087 684 because 2 013 678 × 2 013 678 = 2 013 6782 = 4 054 899 087 684.
As a consequence, 2 013 678 is the square root of 4 054 899 087 684.
The multiples of 2 013 678 are all integers evenly divisible by 2 013 678, that is all numbers such that the remainder of the division by 2 013 678 is zero. There are infinitely many multiples of 2 013 678. The smallest multiples of 2 013 678 are: