Is 2017 a prime number? What are the divisors of 2017?

Is 2017 a prime number?

Yes, 2017 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 2017, the only two divisors are 1 and 2017. Therefore 2017 is a prime number.

As a consequence, 2017 is only a multiple of 1 and 2017.

Therefore year 2017 was a prime year.

Since 2017 is a prime number, 2017 is also a deficient number, that is to say 2017 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 2017 without 2017 itself (that is 1, by definition!).

Parity of 2017

2017 is an odd number, because it is not evenly divisible by 2.

Is 2017 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 2017 is about 44.911.

Thus, the square root of 2017 is not an integer, and therefore 2017 is not a square number.

Anyway, 2017 is a prime number, and a prime number cannot be a perfect square.

What is the square number of 2017?

The square of a number (here 2017) is the result of the product of this number (2017) by itself (i.e., 2017 × 2017); the square of 2017 is sometimes called "raising 2017 to the power 2", or "2017 squared".

The square of 2017 is 4 068 289 because 2017 × 2017 = 20172 = 4 068 289.

As a consequence, 2017 is the square root of 4 068 289.

Number of digits of 2017

2017 is a number with 4 digits.

What are the multiples of 2017?

The multiples of 2017 are all integers evenly divisible by 2017, that is all numbers such that the remainder of the division by 2017 is zero. There are infinitely many multiples of 2017. The smallest multiples of 2017 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 2017 too, since 0 × 2017 = 0
• 2017: indeed, 2017 is a multiple of itself, since 2017 is evenly divisible by 2017 (we have 2017 / 2017 = 1, so the remainder of this division is indeed zero)
• 4 034: indeed, 4 034 = 2017 × 2
• 6 051: indeed, 6 051 = 2017 × 3
• 8 068: indeed, 8 068 = 2017 × 4
• 10 085: indeed, 10 085 = 2017 × 5
• etc.

Nearest numbers from 2017

Find out whether some integer is a prime number