It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 235 013 023 is not a prime number.
For example, 235 013 023 can be divided by 7: 235 013 023 / 7 = 33 573 289.
For 235 013 023 to be a prime number, it would have been required that 235 013 023 has only two divisors, i.e., itself and 1.
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235 013 023 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 235 013 023 is about 15 330.134.
Thus, the square root of 235 013 023 is not an integer, and therefore 235 013 023 is not a square number.
The square of a number (here 235 013 023) is the result of the product of this number (235 013 023) by itself (i.e., 235 013 023 × 235 013 023); the square of 235 013 023 is sometimes called "raising 235 013 023 to the power 2", or "235 013 023 squared".
The square of 235 013 023 is 55 231 120 979 598 528 because 235 013 023 × 235 013 023 = 235 013 0232 = 55 231 120 979 598 528.
As a consequence, 235 013 023 is the square root of 55 231 120 979 598 528.
235 013 023 is a number with 9 digits.
The multiples of 235 013 023 are all integers evenly divisible by 235 013 023, that is all numbers such that the remainder of the division by 235 013 023 is zero. There are infinitely many multiples of 235 013 023. The smallest multiples of 235 013 023 are: