It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 2 423 398 is not a prime number.
For example, 2 423 398 can be divided by 2: 2 423 398 / 2 = 1 211 699.
For 2 423 398 to be a prime number, it would have been required that 2 423 398 has only two divisors, i.e., itself and 1.
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2 423 398 is an even number, because it is evenly divisible by 2: 2 423 398 / 2 = 1 211 699.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 2 423 398 is about 1 556.727.
Thus, the square root of 2 423 398 is not an integer, and therefore 2 423 398 is not a square number.
The square of a number (here 2 423 398) is the result of the product of this number (2 423 398) by itself (i.e., 2 423 398 × 2 423 398); the square of 2 423 398 is sometimes called "raising 2 423 398 to the power 2", or "2 423 398 squared".
The square of 2 423 398 is 5 872 857 866 404 because 2 423 398 × 2 423 398 = 2 423 3982 = 5 872 857 866 404.
As a consequence, 2 423 398 is the square root of 5 872 857 866 404.
The multiples of 2 423 398 are all integers evenly divisible by 2 423 398, that is all numbers such that the remainder of the division by 2 423 398 is zero. There are infinitely many multiples of 2 423 398. The smallest multiples of 2 423 398 are: