# Is 262 a prime number?

It is possible to find out using mathematical methods whether a given integer is a prime number or not.

For 262, the answer is: No, 262 is not a prime number.

The list of all positive divisors (i.e., the list of all integers that divide 262) is as follows: 1, 2, 131, 262.

For 262 to be a prime number, it would have been required that 262 has only two divisors, i.e., itself and 1.

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As a consequence:

For 262 to be a prime number, it would have been required that 262 has only two divisors, i.e., itself and 1.

However, 262 is a **semiprime** (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 262 = 2 x 131, where 2 and 131 are both prime numbers.

### Is 262 a deficient number?

Yes, 262 is a deficient number, that is to say 262 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 262 without 262 itself (that is 1 + 2 + 131 = 134).