Is 3613 a prime number? What are the divisors of 3613?

## Is 3613 a prime number?

Yes, 3613 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 3613, the only two divisors are 1 and 3613. Therefore 3613 is a prime number.

As a consequence, 3613 is only a multiple of 1 and 3613.

Since 3613 is a prime number, 3613 is also a deficient number, that is to say 3613 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 3613 without 3613 itself (that is 1, by definition!).

## Parity of 3613

3613 is an odd number, because it is not evenly divisible by 2.

## Is 3613 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 3613 is about 60.108.

Thus, the square root of 3613 is not an integer, and therefore 3613 is not a square number.

Anyway, 3613 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 3613?

The square of a number (here 3613) is the result of the product of this number (3613) by itself (i.e., 3613 × 3613); the square of 3613 is sometimes called "raising 3613 to the power 2", or "3613 squared".

The square of 3613 is 13 053 769 because 3613 × 3613 = 36132 = 13 053 769.

As a consequence, 3613 is the square root of 13 053 769.

## Number of digits of 3613

3613 is a number with 4 digits.

## What are the multiples of 3613?

The multiples of 3613 are all integers evenly divisible by 3613, that is all numbers such that the remainder of the division by 3613 is zero. There are infinitely many multiples of 3613. The smallest multiples of 3613 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 3613 too, since 0 × 3613 = 0
• 3613: indeed, 3613 is a multiple of itself, since 3613 is evenly divisible by 3613 (we have 3613 / 3613 = 1, so the remainder of this division is indeed zero)
• 7 226: indeed, 7 226 = 3613 × 2
• 10 839: indeed, 10 839 = 3613 × 3
• 14 452: indeed, 14 452 = 3613 × 4
• 18 065: indeed, 18 065 = 3613 × 5
• etc.

## Nearest numbers from 3613

Find out whether some integer is a prime number