Is 37845013 a prime number?

37 845 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 37 845 013 is about 6 151.830.

Thus, the square root of 37 845 013 is not an integer, and therefore 37 845 013 is not a square number.

Anyway, 37 845 013 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 37 845 013) is the result of the product of this number (37 845 013) by itself (i.e., 37 845 013 × 37 845 013); the square of 37 845 013 is sometimes called "raising 37 845 013 to the power 2", or "37 845 013 squared".

The square of 37 845 013 is 1 432 245 008 970 169 because 37 845 013 × 37 845 013 = 37 845 013² = 1 432 245 008 970 169.

As a consequence, 37 845 013 is the square root of 1 432 245 008 970 169.

37 845 013 is a number with 8 digits.

The multiples of 37 845 013 are all integers evenly divisible by 37 845 013, that is all numbers such that the remainder of the division by 37 845 013 is zero. There are infinitely many multiples of 37 845 013. The smallest multiples of 37 845 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 37 845 013 too, since 0 × 37 845 013 = 0
• 37 845 013: indeed, 37 845 013 is a multiple of itself, since 37 845 013 is evenly divisible by 37 845 013 (we have 37 845 013 / 37 845 013 = 1, so the remainder of this division is indeed zero)
• 75 690 026: indeed, 75 690 026 = 37 845 013 × 2
• 113 535 039: indeed, 113 535 039 = 37 845 013 × 3
• 151 380 052: indeed, 151 380 052 = 37 845 013 × 4
• 189 225 065: indeed, 189 225 065 = 37 845 013 × 5
• etc.

• Preceding numbers: …37 845 011, 37 845 012
• Following numbers: 37 845 014, 37 845 015…

Nearest numbers from 37 845 013

• Preceding prime number: 37 844 999
• Following prime number: 37 845 023

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• 37 845 013 est-il un nombre premier ?