It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 3 998 726 is not a prime number.
For example, 3 998 726 can be divided by 2: 3 998 726 / 2 = 1 999 363.
For 3 998 726 to be a prime number, it would have been required that 3 998 726 has only two divisors, i.e., itself and 1.
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3 998 726 is an even number, because it is evenly divisible by 2: 3 998 726 / 2 = 1 999 363.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 3 998 726 is about 1 999.681.
Thus, the square root of 3 998 726 is not an integer, and therefore 3 998 726 is not a square number.
The square of a number (here 3 998 726) is the result of the product of this number (3 998 726) by itself (i.e., 3 998 726 × 3 998 726); the square of 3 998 726 is sometimes called "raising 3 998 726 to the power 2", or "3 998 726 squared".
The square of 3 998 726 is 15 989 809 623 076 because 3 998 726 × 3 998 726 = 3 998 7262 = 15 989 809 623 076.
As a consequence, 3 998 726 is the square root of 15 989 809 623 076.
The multiples of 3 998 726 are all integers evenly divisible by 3 998 726, that is all numbers such that the remainder of the division by 3 998 726 is zero. There are infinitely many multiples of 3 998 726. The smallest multiples of 3 998 726 are: