Is 40248613 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
Yes, 40 248 613 is a prime number.
Indeed, the definition of a prime numbers is to have exactly two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 40 248 613, the only two divisors are 1 and 40 248 613. Therefore 40 248 613 is a prime number.
As a consequence, 40 248 613 is only a multiple of 1 and 40 248 613.
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Since 40248613 is a prime number, 40248613 is also a deficient number, that is to say 40248613 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 40248613 without 40248613 itself (that is 1, by definition!).