It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 491 263 is not a prime number.
For example, 491 263 can be divided by 109: 491 263 / 109 = 4 507.
For 491 263 to be a prime number, it would have been required that 491 263 has only two divisors, i.e., itself and 1.
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491 263 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 491 263 is about 700.902.
Thus, the square root of 491 263 is not an integer, and therefore 491 263 is not a square number.
The square of a number (here 491 263) is the result of the product of this number (491 263) by itself (i.e., 491 263 × 491 263); the square of 491 263 is sometimes called "raising 491 263 to the power 2", or "491 263 squared".
The square of 491 263 is 241 339 335 169 because 491 263 × 491 263 = 491 2632 = 241 339 335 169.
As a consequence, 491 263 is the square root of 241 339 335 169.
The multiples of 491 263 are all integers evenly divisible by 491 263, that is all numbers such that the remainder of the division by 491 263 is zero. There are infinitely many multiples of 491 263. The smallest multiples of 491 263 are: