Is 4937 a prime number? What are the divisors of 4937?

## Is 4937 a prime number?

Yes, 4937 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 4937, the only two divisors are 1 and 4937. Therefore 4937 is a prime number.

As a consequence, 4937 is only a multiple of 1 and 4937.

Since 4937 is a prime number, 4937 is also a deficient number, that is to say 4937 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 4937 without 4937 itself (that is 1, by definition!).

## Parity of 4937

4937 is an odd number, because it is not evenly divisible by 2.

## Is 4937 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 4937 is about 70.264.

Thus, the square root of 4937 is not an integer, and therefore 4937 is not a square number.

Anyway, 4937 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 4937?

The square of a number (here 4937) is the result of the product of this number (4937) by itself (i.e., 4937 × 4937); the square of 4937 is sometimes called "raising 4937 to the power 2", or "4937 squared".

The square of 4937 is 24 373 969 because 4937 × 4937 = 49372 = 24 373 969.

As a consequence, 4937 is the square root of 24 373 969.

## Number of digits of 4937

4937 is a number with 4 digits.

## What are the multiples of 4937?

The multiples of 4937 are all integers evenly divisible by 4937, that is all numbers such that the remainder of the division by 4937 is zero. There are infinitely many multiples of 4937. The smallest multiples of 4937 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 4937 too, since 0 × 4937 = 0
• 4937: indeed, 4937 is a multiple of itself, since 4937 is evenly divisible by 4937 (we have 4937 / 4937 = 1, so the remainder of this division is indeed zero)
• 9 874: indeed, 9 874 = 4937 × 2
• 14 811: indeed, 14 811 = 4937 × 3
• 19 748: indeed, 19 748 = 4937 × 4
• 24 685: indeed, 24 685 = 4937 × 5
• etc.

## Nearest numbers from 4937

Find out whether some integer is a prime number