It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 497 498 is not a prime number.
For example, 497 498 can be divided by 2: 497 498 / 2 = 248 749.
For 497 498 to be a prime number, it would have been required that 497 498 has only two divisors, i.e., itself and 1.
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497 498 is an even number, because it is evenly divisible by 2: 497 498 / 2 = 248 749.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 497 498 is about 705.335.
Thus, the square root of 497 498 is not an integer, and therefore 497 498 is not a square number.
The square of a number (here 497 498) is the result of the product of this number (497 498) by itself (i.e., 497 498 × 497 498); the square of 497 498 is sometimes called "raising 497 498 to the power 2", or "497 498 squared".
The square of 497 498 is 247 504 260 004 because 497 498 × 497 498 = 497 4982 = 247 504 260 004.
As a consequence, 497 498 is the square root of 247 504 260 004.
The multiples of 497 498 are all integers evenly divisible by 497 498, that is all numbers such that the remainder of the division by 497 498 is zero. There are infinitely many multiples of 497 498. The smallest multiples of 497 498 are: