It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 497 602 248 is not a prime number.
For example, 497 602 248 can be divided by 2: 497 602 248 / 2 = 248 801 124.
For 497 602 248 to be a prime number, it would have been required that 497 602 248 has only two divisors, i.e., itself and 1.
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497 602 248 is an even number, because it is evenly divisible by 2: 497 602 248 / 2 = 248 801 124.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 497 602 248 is about 22 307.000.
Thus, the square root of 497 602 248 is not an integer, and therefore 497 602 248 is not a square number.
The square of a number (here 497 602 248) is the result of the product of this number (497 602 248) by itself (i.e., 497 602 248 × 497 602 248); the square of 497 602 248 is sometimes called "raising 497 602 248 to the power 2", or "497 602 248 squared".
The square of 497 602 248 is 247 607 997 214 653 504 because 497 602 248 × 497 602 248 = 497 602 2482 = 247 607 997 214 653 504.
As a consequence, 497 602 248 is the square root of 247 607 997 214 653 504.
497 602 248 is a number with 9 digits.
The multiples of 497 602 248 are all integers evenly divisible by 497 602 248, that is all numbers such that the remainder of the division by 497 602 248 is zero. There are infinitely many multiples of 497 602 248. The smallest multiples of 497 602 248 are: