It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 498 942 013 is not a prime number.
For example, 498 942 013 can be divided by 23: 498 942 013 / 23 = 21 693 131.
For 498 942 013 to be a prime number, it would have been required that 498 942 013 has only two divisors, i.e., itself and 1.
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498 942 013 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 498 942 013 is about 22 337.010.
Thus, the square root of 498 942 013 is not an integer, and therefore 498 942 013 is not a square number.
The square of a number (here 498 942 013) is the result of the product of this number (498 942 013) by itself (i.e., 498 942 013 × 498 942 013); the square of 498 942 013 is sometimes called "raising 498 942 013 to the power 2", or "498 942 013 squared".
The square of 498 942 013 is 248 943 132 336 492 160 because 498 942 013 × 498 942 013 = 498 942 0132 = 248 943 132 336 492 160.
As a consequence, 498 942 013 is the square root of 248 943 132 336 492 160.
498 942 013 is a number with 9 digits.
The multiples of 498 942 013 are all integers evenly divisible by 498 942 013, that is all numbers such that the remainder of the division by 498 942 013 is zero. There are infinitely many multiples of 498 942 013. The smallest multiples of 498 942 013 are: