It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 513 802 016 is not a prime number.
For example, 513 802 016 can be divided by 2: 513 802 016 / 2 = 256 901 008.
For 513 802 016 to be a prime number, it would have been required that 513 802 016 has only two divisors, i.e., itself and 1.
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513 802 016 is an even number, because it is evenly divisible by 2: 513 802 016 / 2 = 256 901 008.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 513 802 016 is about 22 667.201.
Thus, the square root of 513 802 016 is not an integer, and therefore 513 802 016 is not a square number.
The square of a number (here 513 802 016) is the result of the product of this number (513 802 016) by itself (i.e., 513 802 016 × 513 802 016); the square of 513 802 016 is sometimes called "raising 513 802 016 to the power 2", or "513 802 016 squared".
The square of 513 802 016 is 263 992 511 645 664 256 because 513 802 016 × 513 802 016 = 513 802 0162 = 263 992 511 645 664 256.
As a consequence, 513 802 016 is the square root of 263 992 511 645 664 256.
513 802 016 is a number with 9 digits.
The multiples of 513 802 016 are all integers evenly divisible by 513 802 016, that is all numbers such that the remainder of the division by 513 802 016 is zero. There are infinitely many multiples of 513 802 016. The smallest multiples of 513 802 016 are: