Is 564013 a prime number?

564 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 564 013 is about 751.008.

Thus, the square root of 564 013 is not an integer, and therefore 564 013 is not a square number.

Anyway, 564 013 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 564 013) is the result of the product of this number (564 013) by itself (i.e., 564 013 × 564 013); the square of 564 013 is sometimes called "raising 564 013 to the power 2", or "564 013 squared".

The square of 564 013 is 318 110 664 169 because 564 013 × 564 013 = 564 013² = 318 110 664 169.

As a consequence, 564 013 is the square root of 318 110 664 169.

564 013 is a number with 6 digits.

The multiples of 564 013 are all integers evenly divisible by 564 013, that is all numbers such that the remainder of the division by 564 013 is zero. There are infinitely many multiples of 564 013. The smallest multiples of 564 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 564 013 too, since 0 × 564 013 = 0
• 564 013: indeed, 564 013 is a multiple of itself, since 564 013 is evenly divisible by 564 013 (we have 564 013 / 564 013 = 1, so the remainder of this division is indeed zero)
• 1 128 026: indeed, 1 128 026 = 564 013 × 2
• 1 692 039: indeed, 1 692 039 = 564 013 × 3
• 2 256 052: indeed, 2 256 052 = 564 013 × 4
• 2 820 065: indeed, 2 820 065 = 564 013 × 5
• etc.

• Preceding numbers: …564 011, 564 012
• Following numbers: 564 014, 564 015…

Nearest numbers from 564 013

• Preceding prime number: 563 999
• Following prime number: 564 017

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• 564 013 est-il un nombre premier ?