It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 602 023 is not a prime number.
For example, 602 023 can be divided by 47: 602 023 / 47 = 12 809.
For 602 023 to be a prime number, it would have been required that 602 023 has only two divisors, i.e., itself and 1.
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602 023 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 602 023 is about 775.901.
Thus, the square root of 602 023 is not an integer, and therefore 602 023 is not a square number.
The square of a number (here 602 023) is the result of the product of this number (602 023) by itself (i.e., 602 023 × 602 023); the square of 602 023 is sometimes called "raising 602 023 to the power 2", or "602 023 squared".
The square of 602 023 is 362 431 692 529 because 602 023 × 602 023 = 602 0232 = 362 431 692 529.
As a consequence, 602 023 is the square root of 362 431 692 529.
The multiples of 602 023 are all integers evenly divisible by 602 023, that is all numbers such that the remainder of the division by 602 023 is zero. There are infinitely many multiples of 602 023. The smallest multiples of 602 023 are: