It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 602 402 398 is not a prime number.
For example, 602 402 398 can be divided by 2: 602 402 398 / 2 = 301 201 199.
For 602 402 398 to be a prime number, it would have been required that 602 402 398 has only two divisors, i.e., itself and 1.
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602 402 398 is an even number, because it is evenly divisible by 2: 602 402 398 / 2 = 301 201 199.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 602 402 398 is about 24 543.887.
Thus, the square root of 602 402 398 is not an integer, and therefore 602 402 398 is not a square number.
The square of a number (here 602 402 398) is the result of the product of this number (602 402 398) by itself (i.e., 602 402 398 × 602 402 398); the square of 602 402 398 is sometimes called "raising 602 402 398 to the power 2", or "602 402 398 squared".
The square of 602 402 398 is 362 888 649 116 150 400 because 602 402 398 × 602 402 398 = 602 402 3982 = 362 888 649 116 150 400.
As a consequence, 602 402 398 is the square root of 362 888 649 116 150 400.
602 402 398 is a number with 9 digits.
The multiples of 602 402 398 are all integers evenly divisible by 602 402 398, that is all numbers such that the remainder of the division by 602 402 398 is zero. There are infinitely many multiples of 602 402 398. The smallest multiples of 602 402 398 are: