Is 6113 a prime number? What are the divisors of 6113?

## Is 6113 a prime number?

Yes, 6113 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 6113, the only two divisors are 1 and 6113. Therefore 6113 is a prime number.

As a consequence, 6113 is only a multiple of 1 and 6113.

Since 6113 is a prime number, 6113 is also a deficient number, that is to say 6113 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 6113 without 6113 itself (that is 1, by definition!).

## Parity of 6113

6113 is an odd number, because it is not evenly divisible by 2.

## Is 6113 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 6113 is about 78.186.

Thus, the square root of 6113 is not an integer, and therefore 6113 is not a square number.

Anyway, 6113 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 6113?

The square of a number (here 6113) is the result of the product of this number (6113) by itself (i.e., 6113 × 6113); the square of 6113 is sometimes called "raising 6113 to the power 2", or "6113 squared".

The square of 6113 is 37 368 769 because 6113 × 6113 = 61132 = 37 368 769.

As a consequence, 6113 is the square root of 37 368 769.

## Number of digits of 6113

6113 is a number with 4 digits.

## What are the multiples of 6113?

The multiples of 6113 are all integers evenly divisible by 6113, that is all numbers such that the remainder of the division by 6113 is zero. There are infinitely many multiples of 6113. The smallest multiples of 6113 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 6113 too, since 0 × 6113 = 0
• 6113: indeed, 6113 is a multiple of itself, since 6113 is evenly divisible by 6113 (we have 6113 / 6113 = 1, so the remainder of this division is indeed zero)
• 12 226: indeed, 12 226 = 6113 × 2
• 18 339: indeed, 18 339 = 6113 × 3
• 24 452: indeed, 24 452 = 6113 × 4
• 30 565: indeed, 30 565 = 6113 × 5
• etc.

## Nearest numbers from 6113

Find out whether some integer is a prime number