It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 626 738 is not a prime number.
For example, 626 738 can be divided by 2: 626 738 / 2 = 313 369.
For 626 738 to be a prime number, it would have been required that 626 738 has only two divisors, i.e., itself and 1.
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626 738 is an even number, because it is evenly divisible by 2: 626 738 / 2 = 313 369.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 626 738 is about 791.668.
Thus, the square root of 626 738 is not an integer, and therefore 626 738 is not a square number.
The square of a number (here 626 738) is the result of the product of this number (626 738) by itself (i.e., 626 738 × 626 738); the square of 626 738 is sometimes called "raising 626 738 to the power 2", or "626 738 squared".
The square of 626 738 is 392 800 520 644 because 626 738 × 626 738 = 626 7382 = 392 800 520 644.
As a consequence, 626 738 is the square root of 392 800 520 644.
The multiples of 626 738 are all integers evenly divisible by 626 738, that is all numbers such that the remainder of the division by 626 738 is zero. There are infinitely many multiples of 626 738. The smallest multiples of 626 738 are: