It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 637 663 is not a prime number.
For example, 637 663 can be divided by 13: 637 663 / 13 = 49 051.
For 637 663 to be a prime number, it would have been required that 637 663 has only two divisors, i.e., itself and 1.
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637 663 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 637 663 is about 798.538.
Thus, the square root of 637 663 is not an integer, and therefore 637 663 is not a square number.
The square of a number (here 637 663) is the result of the product of this number (637 663) by itself (i.e., 637 663 × 637 663); the square of 637 663 is sometimes called "raising 637 663 to the power 2", or "637 663 squared".
The square of 637 663 is 406 614 101 569 because 637 663 × 637 663 = 637 6632 = 406 614 101 569.
As a consequence, 637 663 is the square root of 406 614 101 569.
The multiples of 637 663 are all integers evenly divisible by 637 663, that is all numbers such that the remainder of the division by 637 663 is zero. There are infinitely many multiples of 637 663. The smallest multiples of 637 663 are: