It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 637 996 is not a prime number.
For example, 637 996 can be divided by 2: 637 996 / 2 = 318 998.
For 637 996 to be a prime number, it would have been required that 637 996 has only two divisors, i.e., itself and 1.
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637 996 is an even number, because it is evenly divisible by 2: 637 996 / 2 = 318 998.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 637 996 is about 798.747.
Thus, the square root of 637 996 is not an integer, and therefore 637 996 is not a square number.
The square of a number (here 637 996) is the result of the product of this number (637 996) by itself (i.e., 637 996 × 637 996); the square of 637 996 is sometimes called "raising 637 996 to the power 2", or "637 996 squared".
The square of 637 996 is 407 038 896 016 because 637 996 × 637 996 = 637 9962 = 407 038 896 016.
As a consequence, 637 996 is the square root of 407 038 896 016.
The multiples of 637 996 are all integers evenly divisible by 637 996, that is all numbers such that the remainder of the division by 637 996 is zero. There are infinitely many multiples of 637 996. The smallest multiples of 637 996 are: