Is 6427 a prime number? What are the divisors of 6427?

## Is 6427 a prime number?

Yes, 6427 is a prime number.

Indeed, the definition of a prime numbers is to have only two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 6427, the only two divisors are 1 and 6427. Therefore 6427 is a prime number.

As a consequence, 6427 is only a multiple of 1 and 6427.

Since 6427 is a prime number, 6427 is also a deficient number, that is to say 6427 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 6427 without 6427 itself (that is 1, by definition!).

## Parity of 6427

6427 is an odd number, because it is not evenly divisible by 2.

## Is 6427 a perfect square number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 6427 is about 80.169.

Thus, the square root of 6427 is not an integer, and therefore 6427 is not a square number.

Anyway, 6427 is a prime number, and a prime number cannot be a perfect square.

## What is the square number of 6427?

The square of a number (here 6427) is the result of the product of this number (6427) by itself (i.e., 6427 × 6427); the square of 6427 is sometimes called "raising 6427 to the power 2", or "6427 squared".

The square of 6427 is 41 306 329 because 6427 × 6427 = 64272 = 41 306 329.

As a consequence, 6427 is the square root of 41 306 329.

## Number of digits of 6427

6427 is a number with 4 digits.

## What are the multiples of 6427?

The multiples of 6427 are all integers evenly divisible by 6427, that is all numbers such that the remainder of the division by 6427 is zero. There are infinitely many multiples of 6427. The smallest multiples of 6427 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 6427 too, since 0 × 6427 = 0
• 6427: indeed, 6427 is a multiple of itself, since 6427 is evenly divisible by 6427 (we have 6427 / 6427 = 1, so the remainder of this division is indeed zero)
• 12 854: indeed, 12 854 = 6427 × 2
• 19 281: indeed, 19 281 = 6427 × 3
• 25 708: indeed, 25 708 = 6427 × 4
• 32 135: indeed, 32 135 = 6427 × 5
• etc.

## Nearest numbers from 6427

Find out whether some integer is a prime number