It is possible to find out using mathematical methods whether a given integer is a prime number or not.
No, 6 565 013 is not a prime number.
For example, 6 565 013 can be divided by 7: 6 565 013 / 7 = 937 859.
For 6 565 013 to be a prime number, it would have been required that 6 565 013 has only two divisors, i.e., itself and 1.
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6 565 013 is an odd number, because it is not evenly divisible by 2.
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A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 6 565 013 is about 2 562.228.
Thus, the square root of 6 565 013 is not an integer, and therefore 6 565 013 is not a square number.
The square of a number (here 6 565 013) is the result of the product of this number (6 565 013) by itself (i.e., 6 565 013 × 6 565 013); the square of 6 565 013 is sometimes called "raising 6 565 013 to the power 2", or "6 565 013 squared".
The square of 6 565 013 is 43 099 395 690 169 because 6 565 013 × 6 565 013 = 6 565 0132 = 43 099 395 690 169.
As a consequence, 6 565 013 is the square root of 43 099 395 690 169.
The multiples of 6 565 013 are all integers evenly divisible by 6 565 013, that is all numbers such that the remainder of the division by 6 565 013 is zero. There are infinitely many multiples of 6 565 013. The smallest multiples of 6 565 013 are: