Is 67492013 a prime number?
It is possible to find out using mathematical methods whether a given integer is a prime number or not.
Yes, 67 492 013 is a prime number.
Indeed, the definition of a prime numbers is to have exactly two distinct positive divisors, 1 and itself. A number is a divisor of another number when the remainder of Euclid’s division of the second one by the first one is zero. Concerning the number 67 492 013, the only two divisors are 1 and 67 492 013. Therefore 67 492 013 is a prime number.
As a consequence, 67 492 013 is only a multiple of 1 and 67 492 013.
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Since 67492013 is a prime number, 67492013 is also a deficient number, that is to say 67492013 is a natural integer that is strictly larger than the sum of its proper divisors, i.e., the divisors of 67492013 without 67492013 itself (that is 1, by definition!).