Is 67980013 a prime number?

67 980 013 is an odd number, because it is not evenly divisible by 2.

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• What is an even number?

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 67 980 013 is about 8 244.999.

Thus, the square root of 67 980 013 is not an integer, and therefore 67 980 013 is not a square number.

Anyway, 67 980 013 is a prime number, and a prime number cannot be a perfect square.

The square of a number (here 67 980 013) is the result of the product of this number (67 980 013) by itself (i.e., 67 980 013 × 67 980 013); the square of 67 980 013 is sometimes called "raising 67 980 013 to the power 2", or "67 980 013 squared".

The square of 67 980 013 is 4 621 282 167 480 169 because 67 980 013 × 67 980 013 = 67 980 013² = 4 621 282 167 480 169.

As a consequence, 67 980 013 is the square root of 4 621 282 167 480 169.

67 980 013 is a number with 8 digits.

The multiples of 67 980 013 are all integers evenly divisible by 67 980 013, that is all numbers such that the remainder of the division by 67 980 013 is zero. There are infinitely many multiples of 67 980 013. The smallest multiples of 67 980 013 are:

• 0: indeed, 0 is divisible by any natural number, and it is thus a multiple of 67 980 013 too, since 0 × 67 980 013 = 0
• 67 980 013: indeed, 67 980 013 is a multiple of itself, since 67 980 013 is evenly divisible by 67 980 013 (we have 67 980 013 / 67 980 013 = 1, so the remainder of this division is indeed zero)
• 135 960 026: indeed, 135 960 026 = 67 980 013 × 2
• 203 940 039: indeed, 203 940 039 = 67 980 013 × 3
• 271 920 052: indeed, 271 920 052 = 67 980 013 × 4
• 339 900 065: indeed, 339 900 065 = 67 980 013 × 5
• etc.

• Preceding numbers: …67 980 011, 67 980 012
• Following numbers: 67 980 014, 67 980 015…

Nearest numbers from 67 980 013

• Preceding prime number: 67 979 999
• Following prime number: 67 980 037

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• 67 980 013 est-il un nombre premier ?